(2x-5)(x^2-x+1)=0

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Solution for (2x-5)(x^2-x+1)=0 equation: 


Simplifying
(2x + -5)(x2 + -1x + 1) = 0

Reorder the terms:
(-5 + 2x)(x2 + -1x + 1) = 0

Reorder the terms:
(-5 + 2x)(1 + -1x + x2) = 0

Multiply (-5 + 2x) * (1 + -1x + x2)
(-5(1 + -1x + x2) + 2x * (1 + -1x + x2)) = 0
((1 * -5 + -1x * -5 + x2 * -5) + 2x * (1 + -1x + x2)) = 0
((-5 + 5x + -5x2) + 2x * (1 + -1x + x2)) = 0
(-5 + 5x + -5x2 + (1 * 2x + -1x * 2x + x2 * 2x)) = 0
(-5 + 5x + -5x2 + (2x + -2x2 + 2x3)) = 0

Reorder the terms:
(-5 + 5x + 2x + -5x2 + -2x2 + 2x3) = 0

Combine like terms: 5x + 2x = 7x
(-5 + 7x + -5x2 + -2x2 + 2x3) = 0

Combine like terms: -5x2 + -2x2 = -7x2
(-5 + 7x + -7x2 + 2x3) = 0

Solving
-5 + 7x + -7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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